Optimal. Leaf size=144 \[ \frac{(b c-a d) (a+b x)^m (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m-1,m;m+1;-\frac{d (a+b x)}{b c-a d}\right )}{4 b^3 d m}-\frac{(b c-a d) (a+b x)^m (c+d x)^{-m} \, _2F_1\left (2,m;m+1;-\frac{d (a+b x)}{b (c+d x)}\right )}{4 b^3 d m} \]
[Out]
________________________________________________________________________________________
Rubi [C] time = 0.0613228, antiderivative size = 93, normalized size of antiderivative = 0.65, number of steps used = 2, number of rules used = 2, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.061, Rules used = {137, 136} \[ \frac{(a+b x)^{m+1} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m F_1\left (m+1;m-2,2;m+2;-\frac{d (a+b x)}{b c-a d},-\frac{2 d (a+b x)}{b c-a d}\right )}{b^3 (m+1)} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
Rule 137
Rule 136
Rubi steps
\begin{align*} \int \frac{(a+b x)^m (c+d x)^{2-m}}{(b c+a d+2 b d x)^2} \, dx &=\frac{\left ((b c-a d)^2 (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m\right ) \int \frac{(a+b x)^m \left (\frac{b c}{b c-a d}+\frac{b d x}{b c-a d}\right )^{2-m}}{(b c+a d+2 b d x)^2} \, dx}{b^2}\\ &=\frac{(a+b x)^{1+m} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m F_1\left (1+m;-2+m,2;2+m;-\frac{d (a+b x)}{b c-a d},-\frac{2 d (a+b x)}{b c-a d}\right )}{b^3 (1+m)}\\ \end{align*}
Mathematica [C] time = 1.37931, size = 308, normalized size = 2.14 \[ \frac{(a+b x)^m (c+d x)^{-m} \left (\frac{\left (\frac{d (a+b x)}{a d-b c}\right )^{-m} \left (4 b (m+1) (c+d x) F_1\left (1-m;-m,1;2-m;\frac{b (c+d x)}{b c-a d},\frac{2 b (c+d x)}{b c-a d}\right )+2 d (m-1) (a+b x) \left (-\frac{b d (a+b x) (c+d x)}{(b c-a d)^2}\right )^m \, _2F_1\left (m,m+1;m+2;\frac{d (a+b x)}{a d-b c}\right )\right )}{d (m-1) (m+1)}-\frac{(b c-a d)^2 \left (\frac{d (a+b x)}{a d+b (c+2 d x)}\right )^{1-m} \left (\frac{b (c+d x)}{a d+b (c+2 d x)}\right )^m F_1\left (1;m,-m;2;\frac{a d-b c}{a d+b (c+2 d x)},\frac{b c-a d}{b c+a d+2 b d x}\right )}{d^2 (a+b x)}\right )}{8 b^3} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.08, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( bx+a \right ) ^{m} \left ( dx+c \right ) ^{2-m}}{ \left ( 2\,bdx+ad+bc \right ) ^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x + a\right )}^{m}{\left (d x + c\right )}^{-m + 2}}{{\left (2 \, b d x + b c + a d\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b x + a\right )}^{m}{\left (d x + c\right )}^{-m + 2}}{4 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 2 \, a b c d + a^{2} d^{2} + 4 \,{\left (b^{2} c d + a b d^{2}\right )} x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x + a\right )}^{m}{\left (d x + c\right )}^{-m + 2}}{{\left (2 \, b d x + b c + a d\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]